The dBm to Watts Calculator converts power levels from dBm, referenced to one milliwatt, to watts. Use this free RF conversion tool for a convenient alternative to manual calculations or spreadsheet conversions.
Enter your parameters below to calculate results.
Use this calculator to convert an absolute power level in dBm to milliwatts or watts, or to convert linear power in watts back to dBm. The conversion is useful for RF, microwave, wireless, optical, and communication-system calculations that span a wide range of power levels.
dBm is referenced to 1 milliwatt. Therefore, 0 dBm equals 1 mW, 10 dBm equals 10 mW, 20 dBm equals 100 mW, and 30 dBm equals 1 W.
Linear power must be greater than zero when converting watts or milliwatts to dBm because the logarithm of zero is undefined. As power approaches zero, the corresponding dBm value approaches negative infinity.
dBm expresses a power level on a base-10 logarithmic scale with a reference power of 1 mW. It is commonly used because a compact range of dBm values can represent linear power levels ranging from fractions of a picowatt to kilowatts.
The reference is essential to the definition: 0 dBm does not mean zero power. It means that the power equals the 1 mW reference.
The watt, symbol W, is the SI unit of power. One watt equals one joule of energy transferred per second:
1 W = 1 J/s
Common submultiples include the milliwatt, microwatt, nanowatt, and picowatt:
Convert dBm to milliwatts with:
PmW = 10PdBm/10
Convert dBm directly to watts with:
PW = 10(PdBm − 30)/10
where PdBm is the power level in dBm, PmW is power in milliwatts, and PW is power in watts.
PW = 10(20 − 30)/10 = 10−1 = 0.1 W
Therefore, 20 dBm equals 100 mW or 0.1 W.
PW = 10(23 − 30)/10 = 0.199526 W
Therefore, 23 dBm is approximately 199.526 mW.
PW = 10(−85 − 30)/10 = 3.16228 × 10−12 W
Therefore, −85 dBm is approximately 3.16228 pW.
Convert watts to dBm with:
PdBm = 10 log10(PW/0.001 W)
An equivalent, convenient form is:
PdBm = 10 log10(PW) + 30
When power is entered in milliwatts:
PdBm = 10 log10(PmW)
PdBm = 10 log10(2) + 30 = 33.0103 dBm
First convert 50 µW to 0.05 mW:
PdBm = 10 log10(0.05) = −13.0103 dBm
| Power Level | Power in Watts | Convenient Linear Unit |
|---|---|---|
| −120 dBm | 0.000000000000001 W | 1 fW |
| −100 dBm | 0.0000000000001 W | 100 fW |
| −90 dBm | 0.000000000001 W | 1 pW |
| −80 dBm | 0.00000000001 W | 10 pW |
| −70 dBm | 0.0000000001 W | 100 pW |
| −60 dBm | 0.000000001 W | 1 nW |
| −50 dBm | 0.00000001 W | 10 nW |
| −40 dBm | 0.0000001 W | 100 nW |
| −30 dBm | 0.000001 W | 1 µW |
| −20 dBm | 0.00001 W | 10 µW |
| −10 dBm | 0.0001 W | 100 µW |
| 0 dBm | 0.001 W | 1 mW |
| 1 dBm | 0.00125893 W | 1.25893 mW |
| 2 dBm | 0.00158489 W | 1.58489 mW |
| 3 dBm | 0.00199526 W | 1.99526 mW |
| 4 dBm | 0.00251189 W | 2.51189 mW |
| 5 dBm | 0.00316228 W | 3.16228 mW |
| 6 dBm | 0.00398107 W | 3.98107 mW |
| 7 dBm | 0.00501187 W | 5.01187 mW |
| 8 dBm | 0.00630957 W | 6.30957 mW |
| 9 dBm | 0.00794328 W | 7.94328 mW |
| 10 dBm | 0.01 W | 10 mW |
| 13 dBm | 0.0199526 W | 19.9526 mW |
| 20 dBm | 0.1 W | 100 mW |
| 23 dBm | 0.199526 W | 199.526 mW |
| 27 dBm | 0.501187 W | 501.187 mW |
| 30 dBm | 1 W | 1 W |
| 33 dBm | 1.99526 W | 1.99526 W |
| 40 dBm | 10 W | 10 W |
| 43 dBm | 19.9526 W | 19.9526 W |
| 50 dBm | 100 W | 100 W |
| 60 dBm | 1000 W | 1 kW |
| Term | Meaning | Reference |
|---|---|---|
| dBm | Absolute logarithmic power level | 1 mW |
| dBW | Absolute logarithmic power level | 1 W |
| dB | Logarithmic ratio between two values | No fixed power reference by itself |
Because 1 W is 1000 times 1 mW, the relationship is:
PdBm = PdBW + 30
Thus 30 dBm equals 0 dBW, and both represent 1 W.
A power-level difference in dB corresponds to a linear power ratio:
Power ratio = 10ΔdB/10
| Change | Power Ratio | Interpretation |
|---|---|---|
| −30 dB | 0.001 | One thousandth of the original power |
| −20 dB | 0.01 | One hundredth of the original power |
| −10 dB | 0.1 | One tenth of the original power |
| −3 dB | 0.501187 | Approximately half the power |
| 0 dB | 1 | No change |
| 3 dB | 1.99526 | Approximately twice the power |
| 6 dB | 3.98107 | Approximately four times the power |
| 10 dB | 10 | Ten times the power |
| 20 dB | 100 | One hundred times the power |
| 30 dB | 1000 | One thousand times the power |
A 3 dB increase is only an approximation to doubling. An exact factor of two corresponds to approximately 3.0103 dB.
Gains and losses expressed as dB ratios can be added algebraically to an absolute dBm power level. For example:
10 dBm + 20 dB gain − 3 dB loss = 27 dBm
The resulting 27 dBm is approximately 0.501187 W.
Two independent power levels must normally be converted to watts or milliwatts, added in linear units, and then converted back to dBm. For two power levels of 30 dBm each:
30 dBm = 1 W; 1 W + 1 W = 2 W; 2 W = 33.0103 dBm
The result is not 60 dBm. When combining coherent signals, the phase relationship and combining network can also affect the measured result, so simple power addition may not describe the complete circuit behavior.
dBm describes power, not voltage. To calculate voltage, you must know the load impedance and the voltage definition. For power delivered to a purely resistive load:
VRMS = √(PW × R)
For a sine wave only:
Vpeak = √2 × VRMS Vpp = 2√2 × VRMS
In a 50 Ω resistive system, 0 dBm corresponds to approximately 0.223607 V RMS and 0.632456 V peak-to-peak for a sine wave. For the same power, a different impedance results in a different voltage.
0 dBm equals 1 mW, which is 0.001 W.
10 dBm equals 10 mW or 0.01 W.
20 dBm equals 100 mW or 0.1 W.
1 W equals 1000 mW, so 10 log10(1000) = 30 dBm.
Yes. A negative dBm value represents a positive power below 1 mW. For example, −30 dBm equals 1 µW. It does not represent negative physical power.
The mathematical conversion between dBm and watts does not depend on frequency. However, the actual delivered or measured power can depend on frequency response, impedance matching, cable loss, calibration, and instrument bandwidth.
A 3 dB increase multiplies power by approximately 1.99526, which is close to two. The exact dB value for a factor of two is 10 log10(2), approximately 3.0103 dB.